Base | Representation |
---|---|
bin | 111101001111001101… |
… | …1111001101101110111 |
3 | 110120102221212112211210 |
4 | 1322132123321231313 |
5 | 4123311311231203 |
6 | 140225154132503 |
7 | 12333604122000 |
oct | 1723633715567 |
9 | 416387775753 |
10 | 131507133303 |
11 | 50854391747 |
12 | 215a1581133 |
13 | c52a1c38a0 |
14 | 65177081a7 |
15 | 364a31b803 |
hex | 1e9e6f9b77 |
131507133303 has 128 divisors (see below), whose sum is σ = 225275904000. Its totient is φ = 67789927296.
The previous prime is 131507133301. The next prime is 131507133313. The reversal of 131507133303 is 303331705131.
It is not a de Polignac number, because 131507133303 - 21 = 131507133301 is a prime.
It is a super-2 number, since 2×1315071333032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131507133301) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 113075200 + ... + 113076362.
It is an arithmetic number, because the mean of its divisors is an integer number (1759968000).
Almost surely, 2131507133303 is an apocalyptic number.
131507133303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
131507133303 is a deficient number, since it is larger than the sum of its proper divisors (93768770697).
131507133303 is a wasteful number, since it uses less digits than its factorization.
131507133303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1386 (or 1372 counting only the distinct ones).
The product of its (nonzero) digits is 8505, while the sum is 30.
Adding to 131507133303 its reverse (303331705131), we get a palindrome (434838838434).
The spelling of 131507133303 in words is "one hundred thirty-one billion, five hundred seven million, one hundred thirty-three thousand, three hundred three".
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