Base | Representation |
---|---|
bin | 11101111001110001010001… |
… | …010111100001000010101011 |
3 | 122020122112201110200100110001 |
4 | 131321301101113201002223 |
5 | 114214203131003111132 |
6 | 1143412205335203431 |
7 | 36462343163132431 |
oct | 3571612127410253 |
9 | 566575643610401 |
10 | 131513263722667 |
11 | 389a4509911792 |
12 | 12900199b16577 |
13 | 584c8558a8ca8 |
14 | 24693c1202d51 |
15 | 1030e660d9ce7 |
hex | 779c515e10ab |
131513263722667 has 2 divisors, whose sum is σ = 131513263722668. Its totient is φ = 131513263722666.
The previous prime is 131513263722611. The next prime is 131513263722691. The reversal of 131513263722667 is 766227362315131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131513263722667 is a prime.
It is not a weakly prime, because it can be changed into another prime (131513263725667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756631861333 + 65756631861334.
It is an arithmetic number, because the mean of its divisors is an integer number (65756631861334).
Almost surely, 2131513263722667 is an apocalyptic number.
131513263722667 is a deficient number, since it is larger than the sum of its proper divisors (1).
131513263722667 is an equidigital number, since it uses as much as digits as its factorization.
131513263722667 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11430720, while the sum is 55.
The spelling of 131513263722667 in words is "one hundred thirty-one trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred twenty-two thousand, six hundred sixty-seven".
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