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131513444315131 is a prime number
BaseRepresentation
bin11101111001110001011100…
…001000011010111111111011
3122020122120012001111101201211
4131321301130020122333323
5114214204013221041011
61143412235310023551
736462350515136164
oct3571613410327773
9566576161441654
10131513444315131
11389a45a184955a
121290022a4a7bb7
13584c884129738
1424693db1b276b
151030e76dadb21
hex779c5c21affb

131513444315131 has 2 divisors, whose sum is σ = 131513444315132. Its totient is φ = 131513444315130.

The previous prime is 131513444315119. The next prime is 131513444315137.

131513444315131 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 131513444315131 - 233 = 131504854380539 is a prime.

It is a super-2 number, since 2×1315134443151312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131513444315137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756722157565 + 65756722157566.

It is an arithmetic number, because the mean of its divisors is an integer number (65756722157566).

Almost surely, 2131513444315131 is an apocalyptic number.

131513444315131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131513444315131 is an equidigital number, since it uses as much as digits as its factorization.

131513444315131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 40.

The spelling of 131513444315131 in words is "one hundred thirty-one trillion, five hundred thirteen billion, four hundred forty-four million, three hundred fifteen thousand, one hundred thirty-one".