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131521033555001 is a prime number
BaseRepresentation
bin11101111001111000100000…
…011111000100110000111001
3122020200021202221222201122222
4131321320200133010300321
5114214320034042230001
61143415532333453425
736463036550461016
oct3571704037046071
9566607687881588
10131521033555001
11389a7836771822
12129017a8041275
1358504c353170c
14246991b0b470d
15103126d2bc61b
hex779e207c4c39

131521033555001 has 2 divisors, whose sum is σ = 131521033555002. Its totient is φ = 131521033555000.

The previous prime is 131521033554971. The next prime is 131521033555027. The reversal of 131521033555001 is 100555330125131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130243421555776 + 1277611999225 = 11412424^2 + 1130315^2 .

It is a cyclic number.

It is not a de Polignac number, because 131521033555001 - 222 = 131521029360697 is a prime.

It is a super-2 number, since 2×1315210335550012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131521033555201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65760516777500 + 65760516777501.

It is an arithmetic number, because the mean of its divisors is an integer number (65760516777501).

Almost surely, 2131521033555001 is an apocalyptic number.

It is an amenable number.

131521033555001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131521033555001 is an equidigital number, since it uses as much as digits as its factorization.

131521033555001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33750, while the sum is 35.

The spelling of 131521033555001 in words is "one hundred thirty-one trillion, five hundred twenty-one billion, thirty-three million, five hundred fifty-five thousand, one".