13152114020 has 12 divisors (see below), whose sum is σ = 27619439484. Its totient is φ = 5260845600.

The previous prime is 13152114007. The next prime is 13152114067. The reversal of 13152114020 is 2041125131.

It can be written as a sum of positive squares in 2 ways, for example, as 4302572836 + 8849541184 = 65594^2 + 94072^2 .

It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 657605701 = 13152114020 / (1 + 3 + 1 + 5 + 2 + 1 + 1 + 4 + 0 + 2 + 0).

It is a junction number, because it is equal to n+sod(n) for n = 13152113983 and 13152114001.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328802831 + ... + 328802870.

It is an arithmetic number, because the mean of its divisors is an integer number (2301619957).

Almost surely, 2^13152114020 is an apocalyptic number.

13152114020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13152114020 is an abundant number, since it is smaller than the sum of its proper divisors (14467325464).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13152114020 is a wasteful number, since it uses less digits than its factorization.

13152114020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 657605710 (or 657605708 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 13152114020 its reverse (2041125131), we get a palindrome (15193239151).

It can be divided in two parts, 131521 and 14020, that added together give a palindrome (145541).

The spelling of 13152114020 in words is "thirteen billion, one hundred fifty-two million, one hundred fourteen thousand, twenty".