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131530243423 = 225479583337
BaseRepresentation
bin111101001111111010…
…0000011110101011111
3110120111120100122222011
41322133310003311133
54123333220242143
6140231341332051
712334304423305
oct1723764036537
9416446318864
10131530243423
1150866436717
12215a9267027
13c531c25807
14651a802275
15364c383e9d
hex1e9fd03d5f

131530243423 has 4 divisors (see below), whose sum is σ = 131531052240. Its totient is φ = 131529434608.

The previous prime is 131530243421. The next prime is 131530243433. The reversal of 131530243423 is 324342035131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131530243423 - 21 = 131530243421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131530243421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66190 + ... + 517147.

It is an arithmetic number, because the mean of its divisors is an integer number (32882763060).

Almost surely, 2131530243423 is an apocalyptic number.

131530243423 is a deficient number, since it is larger than the sum of its proper divisors (808817).

131530243423 is an equidigital number, since it uses as much as digits as its factorization.

131530243423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 808816.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 131530243423 its reverse (324342035131), we get a palindrome (455872278554).

The spelling of 131530243423 in words is "one hundred thirty-one billion, five hundred thirty million, two hundred forty-three thousand, four hundred twenty-three".

Divisors: 1 225479 583337 131530243423