Base | Representation |
---|---|
bin | 11000011111111110… |
… | …10101000010111111 |
3 | 1020221122222211102012 |
4 | 30033333111002333 |
5 | 203414202131112 |
6 | 10013101521435 |
7 | 643643012231 |
oct | 141777250277 |
9 | 36848884365 |
10 | 13153161407 |
11 | 563a686931 |
12 | 2670b7327b |
13 | 1318039859 |
14 | 8cac38251 |
15 | 51eb08022 |
hex | 30ffd50bf |
13153161407 has 4 divisors (see below), whose sum is σ = 13845433080. Its totient is φ = 12460889736.
The previous prime is 13153161397. The next prime is 13153161431. The reversal of 13153161407 is 70416135131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13153161407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13153121407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 346135808 + ... + 346135845.
It is an arithmetic number, because the mean of its divisors is an integer number (3461358270).
Almost surely, 213153161407 is an apocalyptic number.
13153161407 is a deficient number, since it is larger than the sum of its proper divisors (692271673).
13153161407 is an equidigital number, since it uses as much as digits as its factorization.
13153161407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 692271672.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 13153161407 its reverse (70416135131), we get a palindrome (83569296538).
The spelling of 13153161407 in words is "thirteen billion, one hundred fifty-three million, one hundred sixty-one thousand, four hundred seven".
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