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13153240142400 = 2635259831633433
BaseRepresentation
bin1011111101100111101000…
…1101001101001001000000
31201120102210220212022221010
42333121322031031021000
53211000313434024100
643550303132400520
72525201360333061
oct277317215151100
951512726768833
1013153240142400
114211292179886
121585229616140
137454645bc9a7
14336897c50568
1517c22c943750
hexbf67a34d240

13153240142400 has 672 divisors, whose sum is σ = 44699234065920. Its totient is φ = 3384652677120.

The previous prime is 13153240142389. The next prime is 13153240142429. The reversal of 13153240142400 is 424104235131.

13153240142400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3831411084 + ... + 3831414516.

It is an arithmetic number, because the mean of its divisors is an integer number (66516717360).

Almost surely, 213153240142400 is an apocalyptic number.

13153240142400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13153240142400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22349617032960).

13153240142400 is an abundant number, since it is smaller than the sum of its proper divisors (31545993923520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13153240142400 is a wasteful number, since it uses less digits than its factorization.

13153240142400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3763 (or 3748 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 13153240142400 its reverse (424104235131), we get a palindrome (13577344377531).

The spelling of 13153240142400 in words is "thirteen trillion, one hundred fifty-three billion, two hundred forty million, one hundred forty-two thousand, four hundred".