Base | Representation |
---|---|
bin | 11101111010000100000001… |
… | …110001001110011110010010 |
3 | 122020201110201000111211000112 |
4 | 131322010001301032132102 |
5 | 114220020402144342204 |
6 | 1143425340004321322 |
7 | 36463655230164200 |
oct | 3572040161163622 |
9 | 566643630454015 |
10 | 131533403121554 |
11 | 38a02003aa21a5 |
12 | 1290407a6a3242 |
13 | 5851715110475 |
14 | 246a371c14070 |
15 | 10317441de26e |
hex | 77a101c4e792 |
131533403121554 has 48 divisors (see below), whose sum is σ = 230853153595680. Its totient is φ = 56042302317120.
The previous prime is 131533403121553. The next prime is 131533403121557. The reversal of 131533403121554 is 455121304335131.
It is a super-2 number, since 2×1315334031215542 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131533403121553) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 68288414 + ... + 70188134.
It is an arithmetic number, because the mean of its divisors is an integer number (4809440699910).
Almost surely, 2131533403121554 is an apocalyptic number.
131533403121554 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
131533403121554 is a deficient number, since it is larger than the sum of its proper divisors (99319750474126).
131533403121554 is a wasteful number, since it uses less digits than its factorization.
131533403121554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1903863 (or 1903856 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 131533403121554 its reverse (455121304335131), we get a palindrome (586654707456685).
The spelling of 131533403121554 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, four hundred three million, one hundred twenty-one thousand, five hundred fifty-four".
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