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131534350041341 = 1310639518369639
BaseRepresentation
bin11101111010000100111010…
…001101011100000011111101
3122020201120011000022022202202
4131322010322031130003331
5114220024322102310331
61143430013552201245
736464020545651242
oct3572047215340375
9566646130268682
10131534350041341
1138a0244a561035
12129042a3839225
135851836354230
14246a4218a55c9
15103179c3d7ecb
hex77a13a35c0fd

131534350041341 has 8 divisors (see below), whose sum is σ = 141785634157440. Its totient is φ = 121302102666672.

The previous prime is 131534350041271. The next prime is 131534350041349. The reversal of 131534350041341 is 143140053435131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131534350041341 - 226 = 131534282932477 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131534350041295 and 131534350041304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131534350041349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4759171001 + ... + 4759198638.

It is an arithmetic number, because the mean of its divisors is an integer number (17723204269680).

Almost surely, 2131534350041341 is an apocalyptic number.

It is an amenable number.

131534350041341 is a deficient number, since it is larger than the sum of its proper divisors (10251284116099).

131534350041341 is a wasteful number, since it uses less digits than its factorization.

131534350041341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9518370715.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 131534350041341 in words is "one hundred thirty-one trillion, five hundred thirty-four billion, three hundred fifty million, forty-one thousand, three hundred forty-one".

Divisors: 1 13 1063 13819 9518369639 123738805307 10118026926257 131534350041341