Base | Representation |
---|---|
bin | 10011001001000001001… |
… | …111000001100011010010 |
3 | 11122202011022110100002022 |
4 | 103021001033001203102 |
5 | 133022321214401010 |
6 | 2444133202451442 |
7 | 164013465231200 |
oct | 23110117014322 |
9 | 4582138410068 |
10 | 1315354450130 |
11 | 4679253288a6 |
12 | 192b11663b82 |
13 | 970641c70a6 |
14 | 479408b8070 |
15 | 24336e01d55 |
hex | 132413c18d2 |
1315354450130 has 48 divisors (see below), whose sum is σ = 2754495711576. Its totient is φ = 450928800000.
The previous prime is 1315354450099. The next prime is 1315354450133. The reversal of 1315354450130 is 310544535131.
It can be written as a sum of positive squares in 4 ways, for example, as 1148825979889 + 166528470241 = 1071833^2 + 408079^2 .
It is a Harshad number since it is a multiple of its sum of digits (35).
It is not an unprimeable number, because it can be changed into a prime (1315354450133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4431380 + ... + 4718880.
Almost surely, 21315354450130 is an apocalyptic number.
1315354450130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1315354450130 is an abundant number, since it is smaller than the sum of its proper divisors (1439141261446).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1315354450130 is a wasteful number, since it uses less digits than its factorization.
1315354450130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 296859 (or 296852 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 1315354450130 its reverse (310544535131), we get a palindrome (1625898985261).
The spelling of 1315354450130 in words is "one trillion, three hundred fifteen billion, three hundred fifty-four million, four hundred fifty thousand, one hundred thirty".
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