Base | Representation |
---|---|
bin | 10011001001000100000… |
… | …110011001011000111011 |
3 | 11122202021122220112201102 |
4 | 103021010012121120323 |
5 | 133022421021120443 |
6 | 2444142041042015 |
7 | 164014620640016 |
oct | 23110406313073 |
9 | 4582248815642 |
10 | 1315402520123 |
11 | 46794a48056a |
12 | 192b2578630b |
13 | 97071157b83 |
14 | 4794702c37d |
15 | 2433b249cb8 |
hex | 1324419963b |
1315402520123 has 2 divisors, whose sum is σ = 1315402520124. Its totient is φ = 1315402520122.
The previous prime is 1315402520009. The next prime is 1315402520209. The reversal of 1315402520123 is 3210252045131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1315402520123 - 220 = 1315401471547 is a prime.
It is not a weakly prime, because it can be changed into another prime (1315402525123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657701260061 + 657701260062.
It is an arithmetic number, because the mean of its divisors is an integer number (657701260062).
Almost surely, 21315402520123 is an apocalyptic number.
1315402520123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315402520123 is an equidigital number, since it uses as much as digits as its factorization.
1315402520123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 1315402520123 its reverse (3210252045131), we get a palindrome (4525654565254).
The spelling of 1315402520123 in words is "one trillion, three hundred fifteen billion, four hundred two million, five hundred twenty thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •