13154241197921 has 2 divisors, whose sum is σ = 13154241197922. Its totient is φ = 13154241197920.

The previous prime is 13154241197891. The next prime is 13154241197953. The reversal of 13154241197921 is 12979114245131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13077365317696 + 76875880225 = 3616264^2 + 277265^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13154241197921 is a prime.

It is a super-2 number, since 2×13154241197921² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13154241197921.

It is not a weakly prime, because it can be changed into another prime (13154241197021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577120598960 + 6577120598961.

It is an arithmetic number, because the mean of its divisors is an integer number (6577120598961).

Almost surely, 2^{13154241197921} is an apocalyptic number.

It is an amenable number.

13154241197921 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154241197921 is an equidigital number, since it uses as much as digits as its factorization.

13154241197921 is an evil number, because the sum of its binary digits is even.

The product of its digits is 544320, while the sum is 50.

The spelling of 13154241197921 in words is "thirteen trillion, one hundred fifty-four billion, two hundred forty-one million, one hundred ninety-seven thousand, nine hundred twenty-one".