Base | Representation |
---|---|
bin | 1011111101101011010111… |
… | …0111111111011101010011 |
3 | 1201120112101200120001101211 |
4 | 2333122311313333131103 |
5 | 3211004341222324131 |
6 | 43550550333040551 |
7 | 2525235234320032 |
oct | 277326567773523 |
9 | 51515350501354 |
10 | 13154241214291 |
11 | 4211756264a21 |
12 | 1585468926157 |
13 | 745593b13a18 |
14 | 336950b9a719 |
15 | 17c28a7875b1 |
hex | bf6b5dff753 |
13154241214291 has 2 divisors, whose sum is σ = 13154241214292. Its totient is φ = 13154241214290.
The previous prime is 13154241214249. The next prime is 13154241214307. The reversal of 13154241214291 is 19241214245131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13154241214291 - 229 = 13153704343379 is a prime.
It is not a weakly prime, because it can be changed into another prime (13154241214991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577120607145 + 6577120607146.
It is an arithmetic number, because the mean of its divisors is an integer number (6577120607146).
Almost surely, 213154241214291 is an apocalyptic number.
13154241214291 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154241214291 is an equidigital number, since it uses as much as digits as its factorization.
13154241214291 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 40.
The spelling of 13154241214291 in words is "thirteen trillion, one hundred fifty-four billion, two hundred forty-one million, two hundred fourteen thousand, two hundred ninety-one".
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