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131543814565363 is a prime number
BaseRepresentation
bin11101111010001101101110…
…010101101110110111110011
3122020202110120121110221221111
4131322031232111232313303
5114220203213012042423
61143434221045534151
736464504232042604
oct3572155625566763
9566673517427844
10131543814565363
1138a06466a89012
12129060a5414357
1358526b4117cc5
14246aa7c879dab
151031b5327160d
hex77a36e56edf3

131543814565363 has 2 divisors, whose sum is σ = 131543814565364. Its totient is φ = 131543814565362.

The previous prime is 131543814565351. The next prime is 131543814565409. The reversal of 131543814565363 is 363565418345131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131543814565363 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131543814565298 and 131543814565307.

It is not a weakly prime, because it can be changed into another prime (131543814565063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65771907282681 + 65771907282682.

It is an arithmetic number, because the mean of its divisors is an integer number (65771907282682).

Almost surely, 2131543814565363 is an apocalyptic number.

131543814565363 is a deficient number, since it is larger than the sum of its proper divisors (1).

131543814565363 is an equidigital number, since it uses as much as digits as its factorization.

131543814565363 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656000, while the sum is 58.

The spelling of 131543814565363 in words is "one hundred thirty-one trillion, five hundred forty-three billion, eight hundred fourteen million, five hundred sixty-five thousand, three hundred sixty-three".