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131544392156851 is a prime number
BaseRepresentation
bin11101111010001110010000…
…110001000100011010110011
3122020202112001212022122111211
4131322032100301010122303
5114220210403343004401
61143434354241420551
736464524444352032
oct3572162061043263
9566675055278454
10131544392156851
1138a06733021053
121290622693a757
13585277699910b
14246aad546c719
151031b88d14951
hex77a390c446b3

131544392156851 has 2 divisors, whose sum is σ = 131544392156852. Its totient is φ = 131544392156850.

The previous prime is 131544392156839. The next prime is 131544392156867. The reversal of 131544392156851 is 158651293445131.

It is a weak prime.

It is an emirp because it is prime and its reverse (158651293445131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131544392156851 - 29 = 131544392156339 is a prime.

It is not a weakly prime, because it can be changed into another prime (131544392150851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65772196078425 + 65772196078426.

It is an arithmetic number, because the mean of its divisors is an integer number (65772196078426).

Almost surely, 2131544392156851 is an apocalyptic number.

131544392156851 is a deficient number, since it is larger than the sum of its proper divisors (1).

131544392156851 is an equidigital number, since it uses as much as digits as its factorization.

131544392156851 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552000, while the sum is 58.

The spelling of 131544392156851 in words is "one hundred thirty-one trillion, five hundred forty-four billion, three hundred ninety-two million, one hundred fifty-six thousand, eight hundred fifty-one".