Base | Representation |
---|---|
bin | 111101010000100011… |
… | …1010101011001000011 |
3 | 110120120002102201220111 |
4 | 1322201013111121003 |
5 | 4123404312321113 |
6 | 140233441252151 |
7 | 12334661113231 |
oct | 1724107253103 |
9 | 416502381814 |
10 | 131552073283 |
11 | 50877796824 |
12 | 215b4634057 |
13 | c5365c9aa7 |
14 | 651d685951 |
15 | 364e24713d |
hex | 1ea11d5643 |
131552073283 has 2 divisors, whose sum is σ = 131552073284. Its totient is φ = 131552073282.
The previous prime is 131552073259. The next prime is 131552073343. The reversal of 131552073283 is 382370255131.
It is a weak prime.
It is an emirp because it is prime and its reverse (382370255131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131552073283 - 217 = 131551942211 is a prime.
It is not a weakly prime, because it can be changed into another prime (131552073883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65776036641 + 65776036642.
It is an arithmetic number, because the mean of its divisors is an integer number (65776036642).
Almost surely, 2131552073283 is an apocalyptic number.
131552073283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131552073283 is an equidigital number, since it uses as much as digits as its factorization.
131552073283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 131552073283 in words is "one hundred thirty-one billion, five hundred fifty-two million, seventy-three thousand, two hundred eighty-three".
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