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13155242412113 is a prime number
BaseRepresentation
bin1011111101101111000110…
…0011010000100001010001
31201120121222110111011121122
42333123301203100201101
53211013414024141423
643551233540132025
72525302112340104
oct277336143204121
951517873434548
1013155242412113
11421211a42673a
1215856a8097015
137456c3380179
14336a07b3a73b
1517c2e86038c8
hexbf6f18d0851

13155242412113 has 2 divisors, whose sum is σ = 13155242412114. Its totient is φ = 13155242412112.

The previous prime is 13155242412089. The next prime is 13155242412121. The reversal of 13155242412113 is 31121424255131.

13155242412113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10025626670929 + 3129615741184 = 3166327^2 + 1769072^2 .

It is a cyclic number.

It is not a de Polignac number, because 13155242412113 - 216 = 13155242346577 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13155242412313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577621206056 + 6577621206057.

It is an arithmetic number, because the mean of its divisors is an integer number (6577621206057).

Almost surely, 213155242412113 is an apocalyptic number.

It is an amenable number.

13155242412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155242412113 is an equidigital number, since it uses as much as digits as its factorization.

13155242412113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 35.

Adding to 13155242412113 its reverse (31121424255131), we get a palindrome (44276666667244).

The spelling of 13155242412113 in words is "thirteen trillion, one hundred fifty-five billion, two hundred forty-two million, four hundred twelve thousand, one hundred thirteen".