13155243424433 has 4 divisors (see below), whose sum is σ = 14351174644848. Its totient is φ = 11959312204020.

The previous prime is 13155243424333. The next prime is 13155243424481. The reversal of 13155243424433 is 33442434255131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13155243424433 - 2³⁶ = 13086523947697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13155243424033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 597965610191 + ... + 597965610212.

It is an arithmetic number, because the mean of its divisors is an integer number (3587793661212).

Almost surely, 2^{13155243424433} is an apocalyptic number.

It is an amenable number.

13155243424433 is a deficient number, since it is larger than the sum of its proper divisors (1195931220415).

13155243424433 is a wasteful number, since it uses less digits than its factorization.

13155243424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1195931220414.

The product of its digits is 2073600, while the sum is 44.

Adding to 13155243424433 its reverse (33442434255131), we get a palindrome (46597677679564).

The spelling of 13155243424433 in words is "thirteen trillion, one hundred fifty-five billion, two hundred forty-three million, four hundred twenty-four thousand, four hundred thirty-three".