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13155243424481 is a prime number
BaseRepresentation
bin1011111101101111000110…
…0111000111101011100001
31201120121222112101121022202
42333123301213013223201
53211013414304040411
643551234013542545
72525302124054444
oct277336147075341
951517875347282
1013155243424481
11421211aa58304
1215856a84a4a55
137456c3645bc2
14336a07d2165b
1517c2e875383b
hexbf6f19c7ae1

13155243424481 has 2 divisors, whose sum is σ = 13155243424482. Its totient is φ = 13155243424480.

The previous prime is 13155243424333. The next prime is 13155243424529. The reversal of 13155243424481 is 18442434255131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9572990700625 + 3582252723856 = 3094025^2 + 1892684^2 .

It is an emirp because it is prime and its reverse (18442434255131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13155243424481 - 218 = 13155243162337 is a prime.

It is a super-2 number, since 2×131552434244812 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13155243444481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577621712240 + 6577621712241.

It is an arithmetic number, because the mean of its divisors is an integer number (6577621712241).

Almost surely, 213155243424481 is an apocalyptic number.

It is an amenable number.

13155243424481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155243424481 is an equidigital number, since it uses as much as digits as its factorization.

13155243424481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1843200, while the sum is 47.

The spelling of 13155243424481 in words is "thirteen trillion, one hundred fifty-five billion, two hundred forty-three million, four hundred twenty-four thousand, four hundred eighty-one".