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13155243424333 is a prime number
BaseRepresentation
bin1011111101101111000110…
…0111000111101001001101
31201120121222112101121010021
42333123301213013221031
53211013414304034313
643551234013542141
72525302124054143
oct277336147075115
951517875347107
1013155243424333
11421211aa5818a
1215856a84a4951
137456c3645b0a
14336a07d21593
1517c2e875378d
hexbf6f19c7a4d

13155243424333 has 2 divisors, whose sum is σ = 13155243424334. Its totient is φ = 13155243424332.

The previous prime is 13155243424319. The next prime is 13155243424481. The reversal of 13155243424333 is 33342434255131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13150791465604 + 4451958729 = 3626402^2 + 66723^2 .

It is a cyclic number.

It is not a de Polignac number, because 13155243424333 - 213 = 13155243416141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13155243424333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13155243424033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577621712166 + 6577621712167.

It is an arithmetic number, because the mean of its divisors is an integer number (6577621712167).

Almost surely, 213155243424333 is an apocalyptic number.

It is an amenable number.

13155243424333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155243424333 is an equidigital number, since it uses as much as digits as its factorization.

13155243424333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1555200, while the sum is 43.

Adding to 13155243424333 its reverse (33342434255131), we get a palindrome (46497677679464).

The spelling of 13155243424333 in words is "thirteen trillion, one hundred fifty-five billion, two hundred forty-three million, four hundred twenty-four thousand, three hundred thirty-three".