Base | Representation |
---|---|
bin | 1011111101110000000110… |
… | …0011111000100010101110 |
3 | 1201120122200011220102201011 |
4 | 2333130001203320202232 |
5 | 3211014441304332002 |
6 | 43551320333135434 |
7 | 2525311553365516 |
oct | 277340143704256 |
9 | 51518604812634 |
10 | 13155511011502 |
11 | 4212248003402 |
12 | 158576202a57a |
13 | 745736c05612 |
14 | 336a31698846 |
15 | 17c311ead8d7 |
hex | bf7018f88ae |
13155511011502 has 4 divisors (see below), whose sum is σ = 19733266517256. Its totient is φ = 6577755505750.
The previous prime is 13155511011463. The next prime is 13155511011571. The reversal of 13155511011502 is 20511011555131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3288877752874 + ... + 3288877752877.
It is an arithmetic number, because the mean of its divisors is an integer number (4933316629314).
Almost surely, 213155511011502 is an apocalyptic number.
13155511011502 is a deficient number, since it is larger than the sum of its proper divisors (6577755505754).
13155511011502 is an equidigital number, since it uses as much as digits as its factorization.
13155511011502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6577755505753.
The product of its (nonzero) digits is 3750, while the sum is 31.
Adding to 13155511011502 its reverse (20511011555131), we get a palindrome (33666522566633).
The spelling of 13155511011502 in words is "thirteen trillion, one hundred fifty-five billion, five hundred eleven million, eleven thousand, five hundred two".
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