Base | Representation |
---|---|
bin | 11000100000011000… |
… | …10011100010111011 |
3 | 1020221220101122200222 |
4 | 30100030103202323 |
5 | 203421040010011 |
6 | 10013302450255 |
7 | 644013640625 |
oct | 142014234273 |
9 | 36856348628 |
10 | 13156563131 |
11 | 564159a678 |
12 | 267213398b |
13 | 131895acca |
14 | 8cb481c15 |
15 | 52007addb |
hex | 3103138bb |
13156563131 has 2 divisors, whose sum is σ = 13156563132. Its totient is φ = 13156563130.
The previous prime is 13156563083. The next prime is 13156563157. The reversal of 13156563131 is 13136565131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13156563131 - 214 = 13156546747 is a prime.
It is a super-2 number, since 2×131565631312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13156563091 and 13156563100.
It is not a weakly prime, because it can be changed into another prime (13156563181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6578281565 + 6578281566.
It is an arithmetic number, because the mean of its divisors is an integer number (6578281566).
Almost surely, 213156563131 is an apocalyptic number.
13156563131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13156563131 is an equidigital number, since it uses as much as digits as its factorization.
13156563131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24300, while the sum is 35.
The spelling of 13156563131 in words is "thirteen billion, one hundred fifty-six million, five hundred sixty-three thousand, one hundred thirty-one".
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