Base | Representation |
---|---|
bin | 111101010001110010… |
… | …0010111101110001001 |
3 | 110120122221220012020201 |
4 | 1322203210113232021 |
5 | 4124000332130213 |
6 | 140241511452201 |
7 | 12336001036165 |
oct | 1724344275611 |
9 | 416587805221 |
10 | 131593239433 |
11 | 50898a53537 |
12 | 21606387061 |
13 | c541cb1366 |
14 | 6524d1dca5 |
15 | 3652b796dd |
hex | 1ea3917b89 |
131593239433 has 2 divisors, whose sum is σ = 131593239434. Its totient is φ = 131593239432.
The previous prime is 131593239389. The next prime is 131593239523. The reversal of 131593239433 is 334932395131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68546046969 + 63047192464 = 261813^2 + 251092^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131593239433 is a prime.
It is a super-2 number, since 2×1315932394332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131593239233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65796619716 + 65796619717.
It is an arithmetic number, because the mean of its divisors is an integer number (65796619717).
Almost surely, 2131593239433 is an apocalyptic number.
It is an amenable number.
131593239433 is a deficient number, since it is larger than the sum of its proper divisors (1).
131593239433 is an equidigital number, since it uses as much as digits as its factorization.
131593239433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 787320, while the sum is 46.
The spelling of 131593239433 in words is "one hundred thirty-one billion, five hundred ninety-three million, two hundred thirty-nine thousand, four hundred thirty-three".
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