Base | Representation |
---|---|
bin | 10011001001100111110… |
… | …000000101101101000001 |
3 | 11122210211100101210112111 |
4 | 103021213300011231001 |
5 | 133030132131331342 |
6 | 2444321245055321 |
7 | 164035502656015 |
oct | 23114760055501 |
9 | 4583740353474 |
10 | 1316000652097 |
11 | 468127072a0a |
12 | 193071b57541 |
13 | 9713804b411 |
14 | 479a264a545 |
15 | 243739e9217 |
hex | 13267c05b41 |
1316000652097 has 2 divisors, whose sum is σ = 1316000652098. Its totient is φ = 1316000652096.
The previous prime is 1316000652077. The next prime is 1316000652103. The reversal of 1316000652097 is 7902560006131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1282943594241 + 33057057856 = 1132671^2 + 181816^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1316000652097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316000652017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658000326048 + 658000326049.
It is an arithmetic number, because the mean of its divisors is an integer number (658000326049).
Almost surely, 21316000652097 is an apocalyptic number.
It is an amenable number.
1316000652097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316000652097 is an equidigital number, since it uses as much as digits as its factorization.
1316000652097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 1316000652097 in words is "one trillion, three hundred sixteen billion, six hundred fifty-two thousand, ninety-seven".
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