Base | Representation |
---|---|
bin | 11101111011000011010000… |
… | …101111010000110100001011 |
3 | 122020221221221212110121111122 |
4 | 131323003100233100310023 |
5 | 114222123430300000021 |
6 | 1143520445210145455 |
7 | 36501610616136152 |
oct | 3573032057206413 |
9 | 566857855417448 |
10 | 131601300000011 |
11 | 38a28886013996 |
12 | 1291526912228b |
13 | 5857c459161aa |
14 | 246d7733aa599 |
15 | 10333b9d6cbab |
hex | 77b0d0bd0d0b |
131601300000011 has 2 divisors, whose sum is σ = 131601300000012. Its totient is φ = 131601300000010.
The previous prime is 131601300000007. The next prime is 131601300000047. The reversal of 131601300000011 is 110000003106131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131601300000011 - 22 = 131601300000007 is a prime.
It is not a weakly prime, because it can be changed into another prime (131601300090011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65800650000005 + 65800650000006.
It is an arithmetic number, because the mean of its divisors is an integer number (65800650000006).
Almost surely, 2131601300000011 is an apocalyptic number.
131601300000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131601300000011 is an equidigital number, since it uses as much as digits as its factorization.
131601300000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131601300000011 its reverse (110000003106131), we get a palindrome (241601303106142).
The spelling of 131601300000011 in words is "one hundred thirty-one trillion, six hundred one billion, three hundred million, eleven", and thus it is an aban number.
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