Base | Representation |
---|---|
bin | 10011001001101010010… |
… | …011111011111000010001 |
3 | 11122210221100012221202012 |
4 | 103021222103323320101 |
5 | 133030224130302343 |
6 | 2444325421432305 |
7 | 164036534025464 |
oct | 23115223737021 |
9 | 4583840187665 |
10 | 1316043603473 |
11 | 468149339a15 |
12 | 19308440b695 |
13 | 97143c09431 |
14 | 479a822b2db |
15 | 24377680718 |
hex | 1326a4fbe11 |
1316043603473 has 2 divisors, whose sum is σ = 1316043603474. Its totient is φ = 1316043603472.
The previous prime is 1316043603439. The next prime is 1316043603487. The reversal of 1316043603473 is 3743063406131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1233150283729 + 82893319744 = 1110473^2 + 287912^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316043603473 - 222 = 1316039409169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1316043603473.
It is not a weakly prime, because it can be changed into another prime (1316043603673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658021801736 + 658021801737.
It is an arithmetic number, because the mean of its divisors is an integer number (658021801737).
Almost surely, 21316043603473 is an apocalyptic number.
It is an amenable number.
1316043603473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316043603473 is an equidigital number, since it uses as much as digits as its factorization.
1316043603473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 326592, while the sum is 41.
The spelling of 1316043603473 in words is "one trillion, three hundred sixteen billion, forty-three million, six hundred three thousand, four hundred seventy-three".
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