Search a number
-
+
13160437 = 112311719
BaseRepresentation
bin110010001100…
…111111110101
3220202121201121
4302030333311
511332113222
61150023541
7216601423
oct62147765
926677647
1013160437
1174796a4
1244a7bb1
13295a254
141a68113
15124e5c7
hexc8cff5

13160437 has 4 divisors (see below), whose sum is σ = 13173280. Its totient is φ = 13147596.

The previous prime is 13160429. The next prime is 13160447. The reversal of 13160437 is 73406131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73406131 = 157946489.

It is a cyclic number.

It is not a de Polignac number, because 13160437 - 23 = 13160429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13160417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4737 + ... + 6982.

It is an arithmetic number, because the mean of its divisors is an integer number (3293320).

Almost surely, 213160437 is an apocalyptic number.

It is an amenable number.

13160437 is a deficient number, since it is larger than the sum of its proper divisors (12843).

13160437 is a wasteful number, since it uses less digits than its factorization.

13160437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12842.

The product of its (nonzero) digits is 1512, while the sum is 25.

The square root of 13160437 is about 3627.7316604181. The cubic root of 13160437 is about 236.0968014744.

Adding to 13160437 its reverse (73406131), we get a palindrome (86566568).

The spelling of 13160437 in words is "thirteen million, one hundred sixty thousand, four hundred thirty-seven".

Divisors: 1 1123 11719 13160437