Base | Representation |
---|---|
bin | 1011111110000101001000… |
… | …1000001100011110101011 |
3 | 1201121012020201002122201102 |
4 | 2333201102020030132223 |
5 | 3211113022331044143 |
6 | 43554052524512015 |
7 | 2525601520262216 |
oct | 277412210143653 |
9 | 51535221078642 |
10 | 13161157674923 |
11 | 4214685440195 |
12 | 15868790ab60b |
13 | 746126a1a58b |
14 | 3370095ac77d |
15 | 17c542a9e0b8 |
hex | bf85220c7ab |
13161157674923 has 2 divisors, whose sum is σ = 13161157674924. Its totient is φ = 13161157674922.
The previous prime is 13161157674883. The next prime is 13161157674941. The reversal of 13161157674923 is 32947675116131.
13161157674923 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13161157674923 - 230 = 13160083933099 is a prime.
It is not a weakly prime, because it can be changed into another prime (13161127674923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580578837461 + 6580578837462.
It is an arithmetic number, because the mean of its divisors is an integer number (6580578837462).
Almost surely, 213161157674923 is an apocalyptic number.
13161157674923 is a deficient number, since it is larger than the sum of its proper divisors (1).
13161157674923 is an equidigital number, since it uses as much as digits as its factorization.
13161157674923 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5715360, while the sum is 56.
The spelling of 13161157674923 in words is "thirteen trillion, one hundred sixty-one billion, one hundred fifty-seven million, six hundred seventy-four thousand, nine hundred twenty-three".
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