Search a number
-
+
1316122113551 = 7188017444793
BaseRepresentation
bin10011001001101110111…
…111011011011000001111
311122211010210221200022212
4103021232333123120033
5133030404230113201
62444341304301035
7164041506245030
oct23115677333017
94584123850285
101316122113551
11468189692783
121930a677177b
13971572675bb
14479b4826a87
152437e4dcabb
hex1326efdb60f

1316122113551 has 4 divisors (see below), whose sum is σ = 1504139558352. Its totient is φ = 1128104668752.

The previous prime is 1316122113541. The next prime is 1316122113563. The reversal of 1316122113551 is 1553112216131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1316122113551 - 26 = 1316122113487 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1316122113541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94008722390 + ... + 94008722403.

It is an arithmetic number, because the mean of its divisors is an integer number (376034889588).

Almost surely, 21316122113551 is an apocalyptic number.

1316122113551 is a deficient number, since it is larger than the sum of its proper divisors (188017444801).

1316122113551 is an equidigital number, since it uses as much as digits as its factorization.

1316122113551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188017444800.

The product of its digits is 5400, while the sum is 32.

Adding to 1316122113551 its reverse (1553112216131), we get a palindrome (2869234329682).

The spelling of 1316122113551 in words is "one trillion, three hundred sixteen billion, one hundred twenty-two million, one hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 7 188017444793 1316122113551