Base | Representation |
---|---|
bin | 10011001001110110010… |
… | …101011010001000100011 |
3 | 11122211110101210000111101 |
4 | 103021312111122020203 |
5 | 133031132300104011 |
6 | 2444401425055231 |
7 | 164044533405154 |
oct | 23116625321043 |
9 | 4584411700441 |
10 | 1316245316131 |
11 | 468242191699 |
12 | 19311ba87517 |
13 | 97176943135 |
14 | 479c6d3792b |
15 | 2438a2272c1 |
hex | 1327655a223 |
1316245316131 has 2 divisors, whose sum is σ = 1316245316132. Its totient is φ = 1316245316130.
The previous prime is 1316245316123. The next prime is 1316245316159. The reversal of 1316245316131 is 1316135426131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1316245316131 - 23 = 1316245316123 is a prime.
It is a super-3 number, since 3×13162453161313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1316245316101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658122658065 + 658122658066.
It is an arithmetic number, because the mean of its divisors is an integer number (658122658066).
Almost surely, 21316245316131 is an apocalyptic number.
1316245316131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316245316131 is an equidigital number, since it uses as much as digits as its factorization.
1316245316131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 38880, while the sum is 37.
The spelling of 1316245316131 in words is "one trillion, three hundred sixteen billion, two hundred forty-five million, three hundred sixteen thousand, one hundred thirty-one".
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