Base | Representation |
---|---|
bin | 1011111110001101001000… |
… | …1000011011100001001011 |
3 | 1201121101210101002020222022 |
4 | 2333203102020123201023 |
5 | 3211131422114021141 |
6 | 43555050002115055 |
7 | 2526005655151121 |
oct | 277432210334113 |
9 | 51541711066868 |
10 | 13163305220171 |
11 | 42155876a2777 |
12 | 158717834ba8b |
13 | 7463a9914402 |
14 | 3371708b3911 |
15 | 17c61b3a8b4b |
hex | bf8d221b84b |
13163305220171 has 2 divisors, whose sum is σ = 13163305220172. Its totient is φ = 13163305220170.
The previous prime is 13163305220111. The next prime is 13163305220249. The reversal of 13163305220171 is 17102250336131.
13163305220171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (17102250336131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13163305220171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13163305220101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581652610085 + 6581652610086.
It is an arithmetic number, because the mean of its divisors is an integer number (6581652610086).
Almost surely, 213163305220171 is an apocalyptic number.
13163305220171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13163305220171 is an equidigital number, since it uses as much as digits as its factorization.
13163305220171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 35.
The spelling of 13163305220171 in words is "thirteen trillion, one hundred sixty-three billion, three hundred five million, two hundred twenty thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •