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13164223562131 is a prime number
BaseRepresentation
bin1011111110010000100011…
…0111101000000110010011
31201121111011101002212022111
42333210020313220012103
53211140312212442011
643555321045250151
72526040506011665
oct277441067500623
951544141085274
1013164223562131
114215a09012674
121587393a03957
137464c4c60615
1433721a846535
1517c671d0a121
hexbf908de8193

13164223562131 has 2 divisors, whose sum is σ = 13164223562132. Its totient is φ = 13164223562130.

The previous prime is 13164223562107. The next prime is 13164223562173. The reversal of 13164223562131 is 13126532246131.

13164223562131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13164223562131 - 227 = 13164089344403 is a prime.

It is a super-2 number, since 2×131642235621312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13164223662131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6582111781065 + 6582111781066.

It is an arithmetic number, because the mean of its divisors is an integer number (6582111781066).

Almost surely, 213164223562131 is an apocalyptic number.

13164223562131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13164223562131 is an equidigital number, since it uses as much as digits as its factorization.

13164223562131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 155520, while the sum is 40.

The spelling of 13164223562131 in words is "thirteen trillion, one hundred sixty-four billion, two hundred twenty-three million, five hundred sixty-two thousand, one hundred thirty-one".