Base | Representation |
---|---|
bin | 1011111110010000100011… |
… | …0111101000000110010011 |
3 | 1201121111011101002212022111 |
4 | 2333210020313220012103 |
5 | 3211140312212442011 |
6 | 43555321045250151 |
7 | 2526040506011665 |
oct | 277441067500623 |
9 | 51544141085274 |
10 | 13164223562131 |
11 | 4215a09012674 |
12 | 1587393a03957 |
13 | 7464c4c60615 |
14 | 33721a846535 |
15 | 17c671d0a121 |
hex | bf908de8193 |
13164223562131 has 2 divisors, whose sum is σ = 13164223562132. Its totient is φ = 13164223562130.
The previous prime is 13164223562107. The next prime is 13164223562173. The reversal of 13164223562131 is 13126532246131.
13164223562131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13164223562131 - 227 = 13164089344403 is a prime.
It is a super-2 number, since 2×131642235621312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13164223662131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6582111781065 + 6582111781066.
It is an arithmetic number, because the mean of its divisors is an integer number (6582111781066).
Almost surely, 213164223562131 is an apocalyptic number.
13164223562131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13164223562131 is an equidigital number, since it uses as much as digits as its factorization.
13164223562131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 40.
The spelling of 13164223562131 in words is "thirteen trillion, one hundred sixty-four billion, two hundred twenty-three million, five hundred sixty-two thousand, one hundred thirty-one".
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