Base | Representation |
---|---|
bin | 10011001010000000111… |
… | …101101010111000010001 |
3 | 11122211220211022221110221 |
4 | 103022000331222320101 |
5 | 133032013423031031 |
6 | 2444431235153041 |
7 | 164052130223422 |
oct | 23120075527021 |
9 | 4584824287427 |
10 | 1316423642641 |
11 | 468323910a78 |
12 | 19316b745781 |
13 | 971a487c393 |
14 | 47a028b7649 |
15 | 2439abeea11 |
hex | 13280f6ae11 |
1316423642641 has 2 divisors, whose sum is σ = 1316423642642. Its totient is φ = 1316423642640.
The previous prime is 1316423642591. The next prime is 1316423642683. The reversal of 1316423642641 is 1462463246131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1285048960000 + 31374682641 = 1133600^2 + 177129^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316423642641 - 215 = 1316423609873 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316423642141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658211821320 + 658211821321.
It is an arithmetic number, because the mean of its divisors is an integer number (658211821321).
Almost surely, 21316423642641 is an apocalyptic number.
It is an amenable number.
1316423642641 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316423642641 is an equidigital number, since it uses as much as digits as its factorization.
1316423642641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 497664, while the sum is 43.
Adding to 1316423642641 its reverse (1462463246131), we get a palindrome (2778886888772).
The spelling of 1316423642641 in words is "one trillion, three hundred sixteen billion, four hundred twenty-three million, six hundred forty-two thousand, six hundred forty-one".
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