1316424410557 has 4 divisors (see below), whose sum is σ = 1323039608800. Its totient is φ = 1309809212316.

The previous prime is 1316424410533. The next prime is 1316424410563. The reversal of 1316424410557 is 7550144246131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1316424410557 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1316424410057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3307598823 + ... + 3307599220.

It is an arithmetic number, because the mean of its divisors is an integer number (330759902200).

Almost surely, 2^{1316424410557} is an apocalyptic number.

It is an amenable number.

1316424410557 is a deficient number, since it is larger than the sum of its proper divisors (6615198243).

1316424410557 is an equidigital number, since it uses as much as digits as its factorization.

1316424410557 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6615198242.

The product of its (nonzero) digits is 403200, while the sum is 43.

Adding to 1316424410557 its reverse (7550144246131), we get a palindrome (8866568656688).

The spelling of 1316424410557 in words is "one trillion, three hundred sixteen billion, four hundred twenty-four million, four hundred ten thousand, five hundred fifty-seven".