Base | Representation |
---|---|
bin | 10011001010000010111… |
… | …000110101011000010001 |
3 | 11122212000002002021112101 |
4 | 103022002320311120101 |
5 | 133032100204214421 |
6 | 2444434351200401 |
7 | 164053001524666 |
oct | 23120270653021 |
9 | 4585002067471 |
10 | 1316455929361 |
11 | 468340063511 |
12 | 19317a516101 |
13 | 971ab475151 |
14 | 47a06cbda6d |
15 | 2439d97b191 |
hex | 13282e35611 |
1316455929361 has 2 divisors, whose sum is σ = 1316455929362. Its totient is φ = 1316455929360.
The previous prime is 1316455929329. The next prime is 1316455929367. The reversal of 1316455929361 is 1639295546131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 929403971136 + 387051958225 = 964056^2 + 622135^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316455929361 - 25 = 1316455929329 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316455929367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658227964680 + 658227964681.
It is an arithmetic number, because the mean of its divisors is an integer number (658227964681).
Almost surely, 21316455929361 is an apocalyptic number.
It is an amenable number.
1316455929361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316455929361 is an equidigital number, since it uses as much as digits as its factorization.
1316455929361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5248800, while the sum is 55.
The spelling of 1316455929361 in words is "one trillion, three hundred sixteen billion, four hundred fifty-five million, nine hundred twenty-nine thousand, three hundred sixty-one".
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