Base | Representation |
---|---|
bin | 11000100001011000… |
… | …10101101100111001 |
3 | 1020222111012021211012 |
4 | 30100230111230321 |
5 | 203430212214234 |
6 | 10014202443305 |
7 | 644145214145 |
oct | 142054255471 |
9 | 36874167735 |
10 | 13164960569 |
11 | 5646305802 |
12 | 2674b03535 |
13 | 131a60b2c7 |
14 | 8cc62a225 |
15 | 520b890ce |
hex | 310b15b39 |
13164960569 has 2 divisors, whose sum is σ = 13164960570. Its totient is φ = 13164960568.
The previous prime is 13164960551. The next prime is 13164960581. The reversal of 13164960569 is 96506946131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11818951225 + 1346009344 = 108715^2 + 36688^2 .
It is an emirp because it is prime and its reverse (96506946131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13164960569 - 220 = 13163911993 is a prime.
It is a super-2 number, since 2×131649605692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13164960469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6582480284 + 6582480285.
It is an arithmetic number, because the mean of its divisors is an integer number (6582480285).
Almost surely, 213164960569 is an apocalyptic number.
It is an amenable number.
13164960569 is a deficient number, since it is larger than the sum of its proper divisors (1).
13164960569 is an equidigital number, since it uses as much as digits as its factorization.
13164960569 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1049760, while the sum is 50.
The spelling of 13164960569 in words is "thirteen billion, one hundred sixty-four million, nine hundred sixty thousand, five hundred sixty-nine".
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