Base | Representation |
---|---|
bin | 1011111110010100111100… |
… | …0011010010001111011101 |
3 | 1201121121012102201002121002 |
4 | 2333211033003102033131 |
5 | 3211200220130222303 |
6 | 44000033550320045 |
7 | 2526111624165560 |
oct | 277451703221735 |
9 | 51547172632532 |
10 | 13165401023453 |
11 | 42164627247a8 |
12 | 15876621b9025 |
13 | 746651b92cb3 |
14 | 3372ccd8a4d7 |
15 | 17c6e0392788 |
hex | bf94f0d23dd |
13165401023453 has 4 divisors (see below), whose sum is σ = 15046172598240. Its totient is φ = 11284629448668.
The previous prime is 13165401023431. The next prime is 13165401023477. The reversal of 13165401023453 is 35432010456131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13165401023453 - 212 = 13165401019357 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13165401083453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 940385787383 + ... + 940385787396.
It is an arithmetic number, because the mean of its divisors is an integer number (3761543149560).
Almost surely, 213165401023453 is an apocalyptic number.
It is an amenable number.
13165401023453 is a deficient number, since it is larger than the sum of its proper divisors (1880771574787).
13165401023453 is an equidigital number, since it uses as much as digits as its factorization.
13165401023453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1880771574786.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 13165401023453 its reverse (35432010456131), we get a palindrome (48597411479584).
The spelling of 13165401023453 in words is "thirteen trillion, one hundred sixty-five billion, four hundred one million, twenty-three thousand, four hundred fifty-three".
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