Base | Representation |
---|---|
bin | 10011001010001000000… |
… | …111010110110100001001 |
3 | 11122212020012002112210001 |
4 | 103022020013112310021 |
5 | 133032240131404114 |
6 | 2444451202523001 |
7 | 164055115101601 |
oct | 23121007266411 |
9 | 4585205075701 |
10 | 1316543622409 |
11 | 468385609604 |
12 | 1931a3966461 |
13 | 971c369a022 |
14 | 47a147c9c01 |
15 | 243a64ee374 |
hex | 132881d6d09 |
1316543622409 has 2 divisors, whose sum is σ = 1316543622410. Its totient is φ = 1316543622408.
The previous prime is 1316543622397. The next prime is 1316543622461. The reversal of 1316543622409 is 9042263456131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1226766684025 + 89776938384 = 1107595^2 + 299628^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316543622409 - 27 = 1316543622281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316543622469) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658271811204 + 658271811205.
It is an arithmetic number, because the mean of its divisors is an integer number (658271811205).
Almost surely, 21316543622409 is an apocalyptic number.
It is an amenable number.
1316543622409 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316543622409 is an equidigital number, since it uses as much as digits as its factorization.
1316543622409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 46.
The spelling of 1316543622409 in words is "one trillion, three hundred sixteen billion, five hundred forty-three million, six hundred twenty-two thousand, four hundred nine".
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