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13166232525241 is a prime number
BaseRepresentation
bin1011111110011000000010…
…0111001101100110111001
31201121200100101022202121121
42333212000213031212321
53211203421011301431
644000252252305241
72526141341634205
oct277460047154671
951550311282547
1013166232525241
11421684a021364
121587854772221
137467552255a3
1433736b595b05
1517c73d38d611
hexbf9809cd9b9

13166232525241 has 2 divisors, whose sum is σ = 13166232525242. Its totient is φ = 13166232525240.

The previous prime is 13166232525133. The next prime is 13166232525301. The reversal of 13166232525241 is 14252523266131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11195521932841 + 1970710592400 = 3345971^2 + 1403820^2 .

It is an emirp because it is prime and its reverse (14252523266131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13166232525241 - 211 = 13166232523193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13166232525041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6583116262620 + 6583116262621.

It is an arithmetic number, because the mean of its divisors is an integer number (6583116262621).

Almost surely, 213166232525241 is an apocalyptic number.

It is an amenable number.

13166232525241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13166232525241 is an equidigital number, since it uses as much as digits as its factorization.

13166232525241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 518400, while the sum is 43.

The spelling of 13166232525241 in words is "thirteen trillion, one hundred sixty-six billion, two hundred thirty-two million, five hundred twenty-five thousand, two hundred forty-one".