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13166437137551 = 41321132613111
BaseRepresentation
bin1011111110011000110011…
…0011101111110010001111
31201121200212122100010221022
42333212030303233302033
53211204330401400201
644000324442024355
72526146405051435
oct277461463576217
951550778303838
1013166437137551
114216944574645
1215878b11a80bb
13746788736069
1433738a818d55
1517c75130941b
hexbf98ccefc8f

13166437137551 has 4 divisors (see below), whose sum is σ = 13487569750704. Its totient is φ = 12845304524400.

The previous prime is 13166437137533. The next prime is 13166437137571. The reversal of 13166437137551 is 15573173466131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13166437137551 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13166437137493 and 13166437137502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13166437137571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160566306515 + ... + 160566306596.

It is an arithmetic number, because the mean of its divisors is an integer number (3371892437676).

Almost surely, 213166437137551 is an apocalyptic number.

13166437137551 is a deficient number, since it is larger than the sum of its proper divisors (321132613153).

13166437137551 is an equidigital number, since it uses as much as digits as its factorization.

13166437137551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 321132613152.

The product of its digits is 4762800, while the sum is 53.

The spelling of 13166437137551 in words is "thirteen trillion, one hundred sixty-six billion, four hundred thirty-seven million, one hundred thirty-seven thousand, five hundred fifty-one".

Divisors: 1 41 321132613111 13166437137551