Base | Representation |
---|---|
bin | 1011111110011000110011… |
… | …0011101111110010001111 |
3 | 1201121200212122100010221022 |
4 | 2333212030303233302033 |
5 | 3211204330401400201 |
6 | 44000324442024355 |
7 | 2526146405051435 |
oct | 277461463576217 |
9 | 51550778303838 |
10 | 13166437137551 |
11 | 4216944574645 |
12 | 15878b11a80bb |
13 | 746788736069 |
14 | 33738a818d55 |
15 | 17c75130941b |
hex | bf98ccefc8f |
13166437137551 has 4 divisors (see below), whose sum is σ = 13487569750704. Its totient is φ = 12845304524400.
The previous prime is 13166437137533. The next prime is 13166437137571. The reversal of 13166437137551 is 15573173466131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13166437137551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13166437137493 and 13166437137502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13166437137571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160566306515 + ... + 160566306596.
It is an arithmetic number, because the mean of its divisors is an integer number (3371892437676).
Almost surely, 213166437137551 is an apocalyptic number.
13166437137551 is a deficient number, since it is larger than the sum of its proper divisors (321132613153).
13166437137551 is an equidigital number, since it uses as much as digits as its factorization.
13166437137551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 321132613152.
The product of its digits is 4762800, while the sum is 53.
The spelling of 13166437137551 in words is "thirteen trillion, one hundred sixty-six billion, four hundred thirty-seven million, one hundred thirty-seven thousand, five hundred fifty-one".
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