Base | Representation |
---|---|
bin | 1011111110011001011101… |
… | …0100111111001101000001 |
3 | 1201121201022221102120022021 |
4 | 2333212113110333031001 |
5 | 3211210211041423432 |
6 | 44000354144441441 |
7 | 2526153650133166 |
oct | 277462724771501 |
9 | 51551287376267 |
10 | 13166613623617 |
11 | 4216a251571a3 |
12 | 1587940319281 |
13 | 7467b617969c |
14 | 3373a603a06d |
15 | 17c761a6b697 |
hex | bf99753f341 |
13166613623617 has 2 divisors, whose sum is σ = 13166613623618. Its totient is φ = 13166613623616.
The previous prime is 13166613623519. The next prime is 13166613623627. The reversal of 13166613623617 is 71632631666131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8465591765761 + 4701021857856 = 2909569^2 + 2168184^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13166613623617 is a prime.
It is not a weakly prime, because it can be changed into another prime (13166613623627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6583306811808 + 6583306811809.
It is an arithmetic number, because the mean of its divisors is an integer number (6583306811809).
Almost surely, 213166613623617 is an apocalyptic number.
It is an amenable number.
13166613623617 is a deficient number, since it is larger than the sum of its proper divisors (1).
13166613623617 is an equidigital number, since it uses as much as digits as its factorization.
13166613623617 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2939328, while the sum is 52.
The spelling of 13166613623617 in words is "thirteen trillion, one hundred sixty-six billion, six hundred thirteen million, six hundred twenty-three thousand, six hundred seventeen".
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