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131677242762553 is a prime number
BaseRepresentation
bin11101111100001001111111…
…010001111010010100111001
3122021020012222110011200000121
4131330021333101322110321
5114224344443121400203
61144015405031133241
736510236554024135
oct3574117721722471
9567205873150017
10131677242762553
1138a580067a2464
1212927b22214221
135862159308b87
1424732d93723c5
15103536205c0bd
hex77c27f47a539

131677242762553 has 2 divisors, whose sum is σ = 131677242762554. Its totient is φ = 131677242762552.

The previous prime is 131677242762523. The next prime is 131677242762563. The reversal of 131677242762553 is 355267242776131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97293702155049 + 34383540607504 = 9863757^2 + 5863748^2 .

It is a cyclic number.

It is not a de Polignac number, because 131677242762553 - 213 = 131677242754361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131677242762491 and 131677242762500.

It is not a weakly prime, because it can be changed into another prime (131677242762523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65838621381276 + 65838621381277.

It is an arithmetic number, because the mean of its divisors is an integer number (65838621381277).

Almost surely, 2131677242762553 is an apocalyptic number.

It is an amenable number.

131677242762553 is a deficient number, since it is larger than the sum of its proper divisors (1).

131677242762553 is an equidigital number, since it uses as much as digits as its factorization.

131677242762553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 88905600, while the sum is 61.

The spelling of 131677242762553 in words is "one hundred thirty-one trillion, six hundred seventy-seven billion, two hundred forty-two million, seven hundred sixty-two thousand, five hundred fifty-three".