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13167761137 is a prime number
BaseRepresentation
bin11000100001101110…
…00001011011110001
31020222200110120110221
430100313001123301
5203431421324022
610014342453041
7644211060106
oct142067013361
936880416427
1013167761137
115647948923
122675a34181
13131b07bc4b
148ccb58aad
1552103dcc7
hex310dc16f1

13167761137 has 2 divisors, whose sum is σ = 13167761138. Its totient is φ = 13167761136.

The previous prime is 13167761093. The next prime is 13167761143. The reversal of 13167761137 is 73116776131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12634659216 + 533101921 = 112404^2 + 23089^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13167761137 is a prime.

It is a super-2 number, since 2×131677611372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13167761093 and 13167761102.

It is not a weakly prime, because it can be changed into another prime (13167761147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6583880568 + 6583880569.

It is an arithmetic number, because the mean of its divisors is an integer number (6583880569).

Almost surely, 213167761137 is an apocalyptic number.

It is an amenable number.

13167761137 is a deficient number, since it is larger than the sum of its proper divisors (1).

13167761137 is an equidigital number, since it uses as much as digits as its factorization.

13167761137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 111132, while the sum is 43.

The spelling of 13167761137 in words is "thirteen billion, one hundred sixty-seven million, seven hundred sixty-one thousand, one hundred thirty-seven".