Base | Representation |
---|---|
bin | 11101111100001100100100… |
… | …111101111101110000110011 |
3 | 122021020111011011211120201121 |
4 | 131330030210331331300303 |
5 | 114224421141233122403 |
6 | 1144020544531443111 |
7 | 36510365466604321 |
oct | 3574144475756063 |
9 | 567214134746647 |
10 | 131680022551603 |
11 | 38a59202926089 |
12 | 12928579156497 |
13 | 58624b01aa976 |
14 | 24734c0614d11 |
15 | 10354761033bd |
hex | 77c324f7dc33 |
131680022551603 has 2 divisors, whose sum is σ = 131680022551604. Its totient is φ = 131680022551602.
The previous prime is 131680022551523. The next prime is 131680022551709. The reversal of 131680022551603 is 306155220086131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131680022551603 - 225 = 131679988997171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131680022551603.
It is not a weakly prime, because it can be changed into another prime (131680022555603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65840011275801 + 65840011275802.
It is an arithmetic number, because the mean of its divisors is an integer number (65840011275802).
Almost surely, 2131680022551603 is an apocalyptic number.
131680022551603 is a deficient number, since it is larger than the sum of its proper divisors (1).
131680022551603 is an equidigital number, since it uses as much as digits as its factorization.
131680022551603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 131680022551603 in words is "one hundred thirty-one trillion, six hundred eighty billion, twenty-two million, five hundred fifty-one thousand, six hundred three".
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