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131711028641 is a prime number
BaseRepresentation
bin111101010101010010…
…1101100110110100001
3110120222011112111122222
41322222211230312201
54124221010404031
6140301320240425
712341631162023
oct1725245546641
9416864474588
10131711028641
1150949495295
1221639910115
13c560512c0a
146536822013
15365d194e7b
hex1eaa96cda1

131711028641 has 2 divisors, whose sum is σ = 131711028642. Its totient is φ = 131711028640.

The previous prime is 131711028599. The next prime is 131711028671. The reversal of 131711028641 is 146820117131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128878128016 + 2832900625 = 358996^2 + 53225^2 .

It is an emirp because it is prime and its reverse (146820117131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131711028641 is a prime.

It is not a weakly prime, because it can be changed into another prime (131711028671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65855514320 + 65855514321.

It is an arithmetic number, because the mean of its divisors is an integer number (65855514321).

Almost surely, 2131711028641 is an apocalyptic number.

It is an amenable number.

131711028641 is a deficient number, since it is larger than the sum of its proper divisors (1).

131711028641 is an equidigital number, since it uses as much as digits as its factorization.

131711028641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 35.

The spelling of 131711028641 in words is "one hundred thirty-one billion, seven hundred eleven million, twenty-eight thousand, six hundred forty-one".