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131715666262979 is a prime number
BaseRepresentation
bin11101111100101101110001…
…011111111011101111000011
3122021100220011020202201122222
4131330231301133323233003
5114231012141030403404
61144045201452121255
736513066666263231
oct3574556137735703
9567326136681588
10131715666262979
1138a7233386aa97
121293346616622b
135865970893146
142475102405951
151036360437dbe
hex77cb717fbbc3

131715666262979 has 2 divisors, whose sum is σ = 131715666262980. Its totient is φ = 131715666262978.

The previous prime is 131715666262963. The next prime is 131715666262997. The reversal of 131715666262979 is 979262666517131.

Together with next prime (131715666262997) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (979262666517131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131715666262979 - 24 = 131715666262963 is a prime.

It is not a weakly prime, because it can be changed into another prime (131715666262909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65857833131489 + 65857833131490.

It is an arithmetic number, because the mean of its divisors is an integer number (65857833131490).

Almost surely, 2131715666262979 is an apocalyptic number.

131715666262979 is a deficient number, since it is larger than the sum of its proper divisors (1).

131715666262979 is an equidigital number, since it uses as much as digits as its factorization.

131715666262979 is an evil number, because the sum of its binary digits is even.

The product of its digits is 308629440, while the sum is 71.

The spelling of 131715666262979 in words is "one hundred thirty-one trillion, seven hundred fifteen billion, six hundred sixty-six million, two hundred sixty-two thousand, nine hundred seventy-nine".