Search a number
-
+
13174227040 = 25513231132437
BaseRepresentation
bin11000100010011111…
…01100000001100000
31021000010122002000211
430101033230001200
5203440100231130
610015133223504
7644320040122
oct142117540140
937003562024
1013174227040
115650564847
122678031b94
13131c504020
148cd95d212
155218b9a2a
hex3113ec060

13174227040 has 192 divisors, whose sum is σ = 35299587456. Its totient is φ = 4609769472.

The previous prime is 13174227023. The next prime is 13174227103. The reversal of 13174227040 is 4072247131.

It is a junction number, because it is equal to n+sod(n) for n = 13174226993 and 13174227011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5404702 + ... + 5407138.

It is an arithmetic number, because the mean of its divisors is an integer number (183852018).

Almost surely, 213174227040 is an apocalyptic number.

13174227040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13174227040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17649793728).

13174227040 is an abundant number, since it is smaller than the sum of its proper divisors (22125360416).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13174227040 is a wasteful number, since it uses less digits than its factorization.

13174227040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2601 (or 2593 counting only the distinct ones).

The product of its (nonzero) digits is 9408, while the sum is 31.

The spelling of 13174227040 in words is "thirteen billion, one hundred seventy-four million, two hundred twenty-seven thousand, forty".