Base | Representation |
---|---|
bin | 1111101101000… |
… | …11111011100001 |
3 | 100011220021001022 |
4 | 13312203323201 |
5 | 232211242312 |
6 | 21023415225 |
7 | 3156541466 |
oct | 766437341 |
9 | 304807038 |
10 | 131743457 |
11 | 6840289a |
12 | 38154515 |
13 | 213a9211 |
14 | 136d566d |
15 | b875172 |
hex | 7da3ee1 |
131743457 has 2 divisors, whose sum is σ = 131743458. Its totient is φ = 131743456.
The previous prime is 131743427. The next prime is 131743499. The reversal of 131743457 is 754347131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101284096 + 30459361 = 10064^2 + 5519^2 .
It is an emirp because it is prime and its reverse (754347131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131743457 - 26 = 131743393 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131743427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65871728 + 65871729.
It is an arithmetic number, because the mean of its divisors is an integer number (65871729).
Almost surely, 2131743457 is an apocalyptic number.
It is an amenable number.
131743457 is a deficient number, since it is larger than the sum of its proper divisors (1).
131743457 is an equidigital number, since it uses as much as digits as its factorization.
131743457 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 35280, while the sum is 35.
The square root of 131743457 is about 11477.9552621536. The cubic root of 131743457 is about 508.8342681277.
The spelling of 131743457 in words is "one hundred thirty-one million, seven hundred forty-three thousand, four hundred fifty-seven".
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