Base | Representation |
---|---|
bin | 11101111101001000001100… |
… | …100011010100010000110011 |
3 | 122021110121101111002221110021 |
4 | 131331020030203110100303 |
5 | 114231443242040002011 |
6 | 1144110213020344311 |
7 | 36515123030202031 |
oct | 3575101443242063 |
9 | 567417344087407 |
10 | 131744037422131 |
11 | 38a83372623862 |
12 | 12938a636a5097 |
13 | 5868542664c94 |
14 | 24766343ad551 |
15 | 1036e71067471 |
hex | 77d20c8d4433 |
131744037422131 has 2 divisors, whose sum is σ = 131744037422132. Its totient is φ = 131744037422130.
The previous prime is 131744037422119. The next prime is 131744037422197. The reversal of 131744037422131 is 131224730447131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131744037422131 - 223 = 131744029033523 is a prime.
It is a super-2 number, since 2×1317440374221312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131744037422731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65872018711065 + 65872018711066.
It is an arithmetic number, because the mean of its divisors is an integer number (65872018711066).
Almost surely, 2131744037422131 is an apocalyptic number.
131744037422131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131744037422131 is an equidigital number, since it uses as much as digits as its factorization.
131744037422131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 338688, while the sum is 43.
Adding to 131744037422131 its reverse (131224730447131), we get a palindrome (262968767869262).
The spelling of 131744037422131 in words is "one hundred thirty-one trillion, seven hundred forty-four billion, thirty-seven million, four hundred twenty-two thousand, one hundred thirty-one".
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